Question

help

Answer 1

@mathslover

Answer 2

Take the LCM of the denominators first.

Answer 3

2x

Answer 4

?

Answer 5

No, it is actually \(2x^2\) as it will be the lowest common multiple of both \(2x^2\) and \(2x\)

Answer 6

how?

Answer 7

See,

lowest multiple of 2x^2 will be 2x^2 itself

while, lowest multiple of 2x will be 2x.

We have to find the lowest "common" multiple of \(2x^2\) and \(2x\)

So, we will find more multiples of 2x : 2x , 2x^2 , 2x^3 ....

So, we can say that, 2x also has 2x^2 as its multiple.

So, the lowest common multiple will be 2x^2

Answer 8

ohhh okay

Answer 9

So, we have denominator as \(2x^2\) .

Now, we have to solve for numerator.

In order to do that, first divide the LCM by the denominator of first fraction that is :

\(\cfrac{2x^2}{2x^2}\) = 1

Multiply 1 by the numerator of first fraction : 1 * 7 = 7

Now, similarly, do this with the second fraction.

\(\cfrac{2x^2}{2x} = x\)

Multiply x by 11 => 11x

So, you get numerator as 7 + 11x

Answer 10

ohhh cool okay hold on ima write it down

Answer 11

thank you