What is the simplest form of the expression below
2x^2-10x-28 x 6
------------ -----
6x x-7
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OpenStudy (anonymous):
the 6 in the right numerator cancels the one in the left denominator
OpenStudy (anonymous):
so you're left with x(x-7) in the denominator, right?
OpenStudy (anonymous):
now can you factorize the numerator
2x^2-10x-28 = ?
OpenStudy (anonymous):
ya 2x^2-10x-28
------------
x-7
right?
OpenStudy (anonymous):
no only the 6 's cancel each other, the X remains, so the denominator will become
x(x-7)
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OpenStudy (anonymous):
oh okay so 2 (x+2) (x-7)
OpenStudy (anonymous):
@kx2bay
OpenStudy (anonymous):
huh? sorry im bad at math
OpenStudy (anonymous):
yes, correct
OpenStudy (anonymous):
okay but that not the answer @kx2bay
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OpenStudy (anonymous):
right? i have t simplify
OpenStudy (anonymous):
so what's left...?
you're not that bad! you managed to factorize the main part
OpenStudy (anonymous):
\[2(x+2)(x-7) and (x-7)\]
OpenStudy (anonymous):
you have (x-7) in the numerator and in the denominator, don't they cancel each other out?
if yes, then what remains in the numerator and the denominator?
OpenStudy (anonymous):
2(x+2)
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OpenStudy (anonymous):
which i would mutiply right?
OpenStudy (anonymous):
you keep forgetting the x in the denominator, why? it was part of 6x initially and only the 6 was cancelled out
OpenStudy (anonymous):
oh ya sorry because im not writing on peice of paper i do online classes
OpenStudy (anonymous):
2(x+2)
------
x
OpenStudy (anonymous):
always use a piece of paper ;)
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OpenStudy (anonymous):
that's correct, well done!!! Champ :)
OpenStudy (anonymous):
so would it be 2x+4
-----
x @kx2bay
OpenStudy (anonymous):
either that or
2(x+2)
------
x
I'm not sure which is simpler, to me both are simple ;)
OpenStudy (anonymous):
can you help some more? @kx2bay
OpenStudy (anonymous):
sure
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OpenStudy (anonymous):
\[\frac{ x^2yz }{ y^2 } \times \frac{ y }{ 2x}\]
OpenStudy (anonymous):
@kx2bay
OpenStudy (anonymous):
y from right numer. cancels one from the left denom., what's left?
OpenStudy (anonymous):
x^2yz
-------
2xy @kx2bay
OpenStudy (anonymous):
beauty, now can't u do the same with the x's ?
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OpenStudy (anonymous):
xyz
------
2y
OpenStudy (anonymous):
well done, what about the y's now?
OpenStudy (anonymous):
xz
______
2y^2
OpenStudy (anonymous):
but why does the the other y go to the bottom and what are these problems called factoring?
OpenStudy (anonymous):
why did you put y squared in the denom.? I thought the y's cancelled each other out :)
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OpenStudy (anonymous):
factoring = breaking up a big expression into smaller expressions called factors
OpenStudy (anonymous):
so xz
----
2
OpenStudy (anonymous):
Yes that's PERFECT
I hope I didn't confuse u above
OpenStudy (anonymous):
f^2-25 x f
------ ----
5 f-5 @kx2bay
OpenStudy (anonymous):
start small :)
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OpenStudy (anonymous):
do you know how to factorize f^2 - 25
25 can be represented as 5^2
OpenStudy (anonymous):
(f-5) (f-5)
OpenStudy (anonymous):
this is called difference between 2 sqaures
a^2 - b^2 = (a-b)(a+b)
OpenStudy (anonymous):
you almost got it just got the wrong sign ;)
OpenStudy (anonymous):
(f+5)(f+5)
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OpenStudy (anonymous):
no buddy, one has a - and the other +
OpenStudy (anonymous):
look at this:
a^2 - b^2 = (a-b)(a+b)
OpenStudy (anonymous):
ahh okay (f-5)(f+5) f^2-5
-------
5
OpenStudy (anonymous):
was that the final answer that u wrote above, bit squashed next the f+5 ?
OpenStudy (anonymous):
ya
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OpenStudy (anonymous):
no, don't rush, take a step back, use a pen and paper it will help
OpenStudy (anonymous):
(f-5)(f+5) f
------- . --------
5 (f-5)
OpenStudy (anonymous):
(f-5) cancel each other from the numer. and denom. correct ?
if yes then can u write what's left?
OpenStudy (anonymous):
f/5
OpenStudy (anonymous):
and where did the (f+5) go? vanished :)
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OpenStudy (anonymous):
the answer is ...
OpenStudy (anonymous):
f^2+5/5
OpenStudy (anonymous):
go back a step and put it in the form of (f+5).f/5
OpenStudy (anonymous):
now f * (f+5) = f^2 + 5f
do you agree?
OpenStudy (anonymous):
ya soo F^2+5f
---------
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OpenStudy (anonymous):
5
OpenStudy (anonymous):
what are these problems called
OpenStudy (anonymous):
the answer is either
f(f+5)
------
5
or
f^2 + 5f
---------
5