Help please :c Being a smart financial planner, you want to figure out how many months it will be until your principal is paid down to $10,000.00. Solve for t and show all of your work. Note that t will be negative because the number of months will decrease the principal. I started with 10,000=39145(1+.03/12)^12t I ended up with in(10000/39145)/12in(1.0025) =t My only problem is I keep getting t=0.021235284081 for an answer which I believe is wrong.
@ganeshie8 Any ideas?
@phi Help?
Did I get the function wrong when I was isolating t?
you should get \[ \frac{10000}{39145} = 1.0025^{12 t } \] \[ \ln\left( \frac{10000}{39145} \right) = 12 \ln(1.0025) t \] \[ \frac{ \ln\left( \frac{10000}{39145} \right)}{12 \ln(1.0025)} = t \]
ln means "natural log" . You could also use log (base 10) you will get a negative number.
That exactly what I have then I solved it using Mathway and t=0.021235284081 is what I get, I'm just no so confident in myself that it's right.
So I'd re-do the problem but change where "in" is to "log(10)"?
You should get a negative number, not 0.0212 do you have a calculator? or use google: log(10000/39145)= to get the top number
okay let me solve it one sec
I got -0.5926762974
now find 12*log(1.0025)
I got 0.0130125755
So would I divide them both together?
yes, now do -0.5926762974/0.0130125755
type into google -0.5926762974 / 0.0130125755 =
I got -45.5464252561
So that's my answer?
yes, -45.55 months, or -46 months rounded
Thank you so much man!!
yw
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