If 35.5 mL of 0.23 M HCl is required to completely neutralize 20.0 mL of NH3, what is the concentration of the NH3 solution? Show all of the work needed to solve this problem.

HCl + NH3 yields NH4Cl

Question

If 35.5 mL of 0.23 M HCl is required to completely neutralize 20.0 mL of NH3, what is the concentration of the NH3 solution? Show all of the work needed to solve this problem. 

HCl + NH3 yields NH4Cl

anonymous · Answer

Here are some steps you can try to solve this problem:

Determine the number of moles of HCl that reacted. 

The balanced equation shows you the mole ratio between reactants, so once you know how many moles of HCl react, you can determine the number of moles of NH3 that will react.

You know the volume of the NH3 that reacted, so find the molar concentration. Divide the number of moles of NH3 by the volume, in mL.

anonymous · Answer

35.5 * 0.23 = x
x ÷ 20.0 NH3 = Final answer