Question

question below

Answer 1

simplify
\[\cos^2\theta(1+\tan^2\theta)\]

Answer 2

here are the answer choices
\[\cos^2\theta+\sin^2\theta\]
\[\cos^2\theta\]
1
-1

Answer 3

\[\cos^2\theta(1+\tan^2\theta)\]
\[1+\tan^2\theta=\sec^2\theta\]
so

\[\cos^2\theta \sec^2\theta\]
take the sqrt of both

\[\cos \theta \sec \theta\]
\[\cos \theta = 1/\sec \theta\]
so we have

\[(1/\sec \theta)(\sec \theta)\]

\[\sec \theta/\sec \theta\]

which equals 1

Answer 4

Confirmed by my friend here :) http://www.wolframalpha.com/input/?i=%28cos^2theta%29%281%2Btan^2theta%29

Answer 5

what is sec?

Answer 6

Secant. It's like sine, cosine, tangent, all that jazz. These problems can be solved using trigonometric identities: http://www.purplemath.com/modules/idents.htm

Answer 7

oh ok thank you! :)

Answer 8

could you help me with one more?

Answer 9

Sure!

Answer 10

do you want me to open a new question?

Answer 11

You don't have to. Whatever you prefer :)