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Mathematics 17 Online
OpenStudy (sleepyjess):

@girlnotonfire

OpenStudy (sleepyjess):

If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ?

OpenStudy (sleepyjess):

sin Θ = square root 2 over 2; tan Θ = −1 sin Θ = negative square root 2 over 2; tan Θ = 1 sin Θ = square root 2 over 2; tan Θ = negative square root 2 sin Θ = negative square root 2 over 2; tan Θ = −1

OpenStudy (cydney_morgan):

If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ? If 3 pi over 2 < Θ < 2π Then the signs of sinx and tanx are both negative. cos(x) = sqrt(2)/2. So sin(x) = -sqrt(2)/2 and tan(x) = -1. sin Θ = square root 2 over 2; tan Θ = −1 sin Θ = negative square root 2 over 2; tan Θ = 1 sin Θ = square root 2 over 2; tan Θ = negative square root 2 sin Θ = negative square root 2 over 2; tan Θ = −1

OpenStudy (sleepyjess):

how do you know that they are both going to be negative?

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