Hi! Ok. So I have 50.00mL AgNO3 solution that reacts with excess Na2CO3. Ag2CO3 is formed.

So far I have:
2 AgNO3 + Na2CO3 -- Ag2CO3 + 2 NaNO3

Now, 2.76g of the precipitate Ag2CO3 is formed. Is this = to 0.01 moles?

How many moles of the solution react?

And what would the concentration of that AgNO3 solution be? (mol/L)
Thanks so much!

Question

Hi! Ok. So I have 50.00mL AgNO3 solution that reacts with excess Na2CO3. Ag2CO3 is formed. 

So far I have: 
2 AgNO3 + Na2CO3 --> Ag2CO3 + 2 NaNO3 

Now, 2.76g of the precipitate Ag2CO3 is formed. Is this = to 0.01 moles? 

How many moles of the solution react? 

And what would the concentration of that AgNO3 solution be? (mol/L)
Thanks so much!

anonymous · Answer

Just realized I posted this in Math instead of Chem… Sorry! Hopefully some of you math people can still help me out :)