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Hi! Ok. So I have 50.00mL AgNO3 solution that reacts with excess Na2CO3. Ag2CO3 is formed. So far I have: 2 AgNO3 + Na2CO3 --> Ag2CO3 + 2 NaNO3 Now, 2.76g of the precipitate Ag2CO3 is formed. Is this = to 0.01 moles? How many moles of the solution react? And what would the concentration of that AgNO3 solution be? (mol/L) Thanks so much!
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Just realized I posted this in Math instead of Chem… Sorry! Hopefully some of you math people can still help me out :)
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