Question

someone please check if i correctly integrated this question.

Answer 1

go ahead and post it, eh?

Answer 2

thanks in advance, and sorry that it's in vertical

Answer 3

I think you're missing a negative sign...

Answer 4

@whpalmer4 can you show me in a work?

Answer 5

I need to go, so I don't have time to figure out where exactly you made the error, but both terms should be negative...

Answer 6

@whpalmer4 thanks for your time

Answer 7

@Loser66 plz help me when you can

Answer 8

Loser is not here, how about OOOPS? hehehe

Answer 9

http://www.wolframalpha.com/input/?i=int+%28%28sqrt%28x^2-9%29%2Fx^3%29dx

Answer 10

@OOOPS wolfram alpha might have it wrong on this question

Answer 11

That seems unlikely, as if you ask it to differentiate the result, you get your integral back:

http://www.wolframalpha.com/input/?i=differentiate+-sqrt%28x%5E2-9%29%2F%282x%5E2%29+-+%281%2F6%29arctan%283%2Fsqrt%28x%5E2-9%29%29%2BC

Answer 12

Here's how it arrived at the integral result:

Answer 13

@whpalmer4 The derivative clearly explains this.

https://www.wolframalpha.com/input/?i=derive+1%2F6arctan%28sqrt%28x%5E2-9%29%2F3%29-sqrt%28x%5E2-9%29%2F%282x%5E2%29

Answer 14

and for 1/6arctan(sqrt(x^2-9)/3)=-1/6arctan(3/sqrt(x^2-9)
x does not exist