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Mathematics 15 Online
OpenStudy (askme12345):

Is there sufficient evidence to conclude....

OpenStudy (askme12345):

Fish are unsafe to eat is there PCB exceeds over 5 PPB. A random sample of 10 fish taken from a local lake resulted in the concentrations below 2.6, 6.6, 4.8, 5.4, 5.1, 4.5, 6.9, 4.9, 3.7, 3.8 is there sufficient evidence to conclude that the mean PCB exceeds 5 ppb? use alpha = .05

jimthompson5910 (jim_thompson5910):

how far did you get?

OpenStudy (askme12345):

Honestly not sure how to work around this one! I know I need to start off with a HO and an Ha which i would say is HO = 4.83 HA > 4.83

jimthompson5910 (jim_thompson5910):

where are you getting 4.83 ?

jimthompson5910 (jim_thompson5910):

oh that's xbar

jimthompson5910 (jim_thompson5910):

no, the hypothesis test for the mean always has mu in the hypothesis

jimthompson5910 (jim_thompson5910):

Ho: mu = ??? Ha: mu > ???

jimthompson5910 (jim_thompson5910):

we don't need to test xbar because we know exactly what it is...4.83 we don't know much about the population, which is why we're conducting the test on the population mean mu

OpenStudy (askme12345):

oh, so basically we cant write a hypothesis bc we cant calculate the mu?

jimthompson5910 (jim_thompson5910):

no, we write the hypothesis based on mu

jimthompson5910 (jim_thompson5910):

so what are the hypotheses?

OpenStudy (askme12345):

ho: 5=mu hu: 5 > mu ? Sorry if this is wrong i just never get stats haha

jimthompson5910 (jim_thompson5910):

you sorta have the right idea

jimthompson5910 (jim_thompson5910):

it's just mixed up

jimthompson5910 (jim_thompson5910):

the variable should be on the left side

jimthompson5910 (jim_thompson5910):

Ho: mu = 5 Ha: mu > 5

jimthompson5910 (jim_thompson5910):

so the status quo is that the mean is 5 the alternative challenge is the mean is more than 5

OpenStudy (askme12345):

okay! getting it .. slowly

jimthompson5910 (jim_thompson5910):

what kind of test is this? one tailed? or two tailed?

OpenStudy (askme12345):

one tailed?

jimthompson5910 (jim_thompson5910):

to the left? or to the right?

OpenStudy (askme12345):

to the right? bc we want to see if it exceeds 5?

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

so the p value will be found by finding the area to the right of the test statistic

jimthompson5910 (jim_thompson5910):

we'll need that next, so what is the test statistic

OpenStudy (askme12345):

okay so test statistic would be (4.83-5)/(1.30/3.26) -.17/.40 = -.425

jimthompson5910 (jim_thompson5910):

I'm getting t = (xbar - mu)/(s/sqrt(n)) t = (4.83 - 5)/(1.301324112/sqrt(10)) t = -0.41310784705466

OpenStudy (askme12345):

Looks like we used the same #'s just rounded the S differently

jimthompson5910 (jim_thompson5910):

yeah

jimthompson5910 (jim_thompson5910):

btw, sqrt(10) = 3.16 roughly not 3.26

jimthompson5910 (jim_thompson5910):

anyways, I'd use the longer decimal expansions and don't round until you get to the final answer

OpenStudy (askme12345):

Okay thats fine. so ill keep -0.41310 for the test stat.

jimthompson5910 (jim_thompson5910):

t = -0.4131 works, yeah

jimthompson5910 (jim_thompson5910):

now find the area to the right of t = -0.4131 to calculate the p value

OpenStudy (askme12345):

16.92? I looked at df=9 and .05 on a p value table

jimthompson5910 (jim_thompson5910):

look in the row df = 9

jimthompson5910 (jim_thompson5910):

between which two columns is 0.413 located?

jimthompson5910 (jim_thompson5910):

try this table http://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf

OpenStudy (askme12345):

between .50 and .25 the # are 0.000 & 0.703

jimthompson5910 (jim_thompson5910):

so that means the area to the right of 0.413 is between 0.5 and 0.25 by symmetry, the area to the left of -0.413 is between 0.5 and 0.25 so the area to the right of -0.413 is between between 0.5 and 0.75 (I subtracted 0.5 from 1 to get 0.5 and I subtracted 0.25 from 1 to get 0.75)

jimthompson5910 (jim_thompson5910):

it turns out that the area to the right of -0.413 is 0.6554018441 but we don't need the actual p value

jimthompson5910 (jim_thompson5910):

if we know the p value is between 0.5 and 0.75, then what can we say about the null hypothesis?

jimthompson5910 (jim_thompson5910):

alpha = .05

OpenStudy (askme12345):

we fail to reject! bc the p is greater than alpha

jimthompson5910 (jim_thompson5910):

much much greater (than even the largest significance level usually used, alpha = 0.10)

jimthompson5910 (jim_thompson5910):

you have the correct decision

jimthompson5910 (jim_thompson5910):

so what does that mean? how do we interpret failing to reject the null?

OpenStudy (askme12345):

Yes there is sufficient evidence that says pcb exceeds 5

jimthompson5910 (jim_thompson5910):

go back to the null and alternative hypothesis you set up

jimthompson5910 (jim_thompson5910):

we are failing to reject Ho (since the p value is larger than alpha)

OpenStudy (askme12345):

okay so we fail to reject ho, which means it is true. so mu does equal 5. so it does not exceed 5, there is not enough sig. evidence

jimthompson5910 (jim_thompson5910):

it doesn't necessarily mean the null is true we just don't have enough statistical evidence to disprove and say it's false

jimthompson5910 (jim_thompson5910):

so yes, there is not a sufficient amount of evidence to conclude that the mean PCB exceeds 5 ppb

OpenStudy (askme12345):

Okay. Thank so much for having patience - you really made this clear!!

jimthompson5910 (jim_thompson5910):

I'm glad I have

OpenStudy (askme12345):

Yup - thanks again! 1 last question in this death trap of a hw.. haha

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