Is there sufficient evidence to conclude....
Fish are unsafe to eat is there PCB exceeds over 5 PPB. A random sample of 10 fish taken from a local lake resulted in the concentrations below 2.6, 6.6, 4.8, 5.4, 5.1, 4.5, 6.9, 4.9, 3.7, 3.8 is there sufficient evidence to conclude that the mean PCB exceeds 5 ppb? use alpha = .05
how far did you get?
Honestly not sure how to work around this one! I know I need to start off with a HO and an Ha which i would say is HO = 4.83 HA > 4.83
where are you getting 4.83 ?
oh that's xbar
no, the hypothesis test for the mean always has mu in the hypothesis
Ho: mu = ??? Ha: mu > ???
we don't need to test xbar because we know exactly what it is...4.83 we don't know much about the population, which is why we're conducting the test on the population mean mu
oh, so basically we cant write a hypothesis bc we cant calculate the mu?
no, we write the hypothesis based on mu
so what are the hypotheses?
ho: 5=mu hu: 5 > mu ? Sorry if this is wrong i just never get stats haha
you sorta have the right idea
it's just mixed up
the variable should be on the left side
Ho: mu = 5 Ha: mu > 5
so the status quo is that the mean is 5 the alternative challenge is the mean is more than 5
okay! getting it .. slowly
what kind of test is this? one tailed? or two tailed?
one tailed?
to the left? or to the right?
to the right? bc we want to see if it exceeds 5?
correct
so the p value will be found by finding the area to the right of the test statistic
we'll need that next, so what is the test statistic
okay so test statistic would be (4.83-5)/(1.30/3.26) -.17/.40 = -.425
I'm getting t = (xbar - mu)/(s/sqrt(n)) t = (4.83 - 5)/(1.301324112/sqrt(10)) t = -0.41310784705466
Looks like we used the same #'s just rounded the S differently
yeah
btw, sqrt(10) = 3.16 roughly not 3.26
anyways, I'd use the longer decimal expansions and don't round until you get to the final answer
Okay thats fine. so ill keep -0.41310 for the test stat.
t = -0.4131 works, yeah
now find the area to the right of t = -0.4131 to calculate the p value
16.92? I looked at df=9 and .05 on a p value table
look in the row df = 9
between which two columns is 0.413 located?
try this table http://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf
between .50 and .25 the # are 0.000 & 0.703
so that means the area to the right of 0.413 is between 0.5 and 0.25 by symmetry, the area to the left of -0.413 is between 0.5 and 0.25 so the area to the right of -0.413 is between between 0.5 and 0.75 (I subtracted 0.5 from 1 to get 0.5 and I subtracted 0.25 from 1 to get 0.75)
it turns out that the area to the right of -0.413 is 0.6554018441 but we don't need the actual p value
if we know the p value is between 0.5 and 0.75, then what can we say about the null hypothesis?
alpha = .05
we fail to reject! bc the p is greater than alpha
much much greater (than even the largest significance level usually used, alpha = 0.10)
you have the correct decision
so what does that mean? how do we interpret failing to reject the null?
Yes there is sufficient evidence that says pcb exceeds 5
go back to the null and alternative hypothesis you set up
we are failing to reject Ho (since the p value is larger than alpha)
okay so we fail to reject ho, which means it is true. so mu does equal 5. so it does not exceed 5, there is not enough sig. evidence
it doesn't necessarily mean the null is true we just don't have enough statistical evidence to disprove and say it's false
so yes, there is not a sufficient amount of evidence to conclude that the mean PCB exceeds 5 ppb
Okay. Thank so much for having patience - you really made this clear!!
I'm glad I have
Yup - thanks again! 1 last question in this death trap of a hw.. haha
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