Calculate the amount of charcoal required to effectively decolorizethe salicylic acid. Information given to me; - crude salicylic acid= 1g, containing 0.2% Alizarin Yellow R - (not sure if this is important, but we add 25ml of water) - activated 1g of charcoal has an area of 800m2 - area of contact of Ali Yellow R is approximately 200A2 (A=1x10-10m) - alizarin yellow R (M.W. of 287.23, formula isC13H9N3O5)
Question (has 4 parts) a) Calculate weight of Alzarin Yellow R in the 1g sample ofsalicylic acid. b) Convert this to the number of moles, and thence the # ofmolecules. c) Calculate the total area occupied by these molecules. d) Calculate the weight of activated charcoal needed that wouldprovide this area.
i keep getting a weird number
sorry i don't remember.
NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO!!!!
i can show u my calculation if u like
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