I'm literally about to cry from this problem, medal and fan will be rewarded for help. :( Linda is studying the sale of a particular brand of cereals from the year 1993 to 2004. She writes the following function to model the sale of the cereal S(t), in million dollars, after t years: S(t) = t^2 + 5t + 52 What is the average rate of change of the sale of the cereal from the first year to the fourth year? Show your work.
@undeadknight26
@jim_thompson5910
First you'll need to calculate S(1) and S(4)
Right
what do you get for each?
I got it, let me type it up:
\[\frac{ y^2 - y^1 }{ x^2 - x^1 }\]
right idea, but the notation is off
The notation? Would you mind explaining a little more? :)
basically you're calculating the slope through (x1,y1) and (x2,y2) where y1 = S(x1) and y2 = S(x2)
Ok
well you're not squaring y, it's y sub 2 (the 2 is below the y)
So, 1997 = S(4), 1993 = S(1)
not quite
you plug t = 1 into S(t) to find S(1)
OOOOooooohhhh!
So:
uuuuuhhhh.....could you please explain more please?
S(t) = t^2 + 5t + 52 S(1) = (1)^2 + 5(1) + 52 ... replace EVERY copy of t with 1 S(1) = ???
Oh poop, that's what I was going to put, but I was thinking of a different equation, hold on one sec, let me solve it! XD
\[S(1) = 1^2 + 5(1) + 52 = S(1) = 58?\]
good
S(4) = ??
Yeeeesssss...hehehe....let me solve that one...
\[S(4) = 4^2 + 5(4) + 52 = S(4) = 88\]
correct
OOOOOOOHHHHHHH.....I GOT IT. PLUG THOSE INTO THE AVERAGE RATE OF CHANGE RIGHT?
The formula?
exactly, visually the average rate of change is just the slope of the line through the two points
I understand now! I forgot the AROC is the slope! Ok, plug those into the parts in the formula and I'll get my answer, correct good sir?
that is correct
Alright, I'll answer it, hold on a sec.:
\[\frac{ 88 - 58 }{ 4 - 1 } = \frac{ 30 }{ 3 } = 10 million dollars!!!!!!\]
10 million is correct, but the units are dollars per yer
Mr. Thompson, would you mind deleting your answer about the "now use them to find the slope through (1,58) and (4,88) ?" I don't want other people to see how you got the answer, like just taking the answer without knowing what it means.
fair enough
Actually, I think others would benefit from seeing what jim wrote to you. He discusses a method, but does not provide an answer!
probably best to delete the whole question then (or at least that final answer) if you're concerned about that
Ok, I shall do that. @mathmale you are correct about that, but I know some students who just look at these questions, and take the answers. :(
Why? You will help other people?? :\
I know, but...I guess you're right.
I won't say the answer. How about that? :)
Your discussion with Jim has been a very good one. I see no harm done by leaving it posted as is.
Ok, I hope I didn't break any rules @mathmale
Relax. Not at all! On the contrary, you were a thoughtful participant in this discussion. What I'd give to see others participate as much as you have! Why not go on to some new problems now? Good luck!
Taw, thank you for the kind words! I shall continue on my journey for new math problems to conquer. Farewell!
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