How many liters of 5.4 M calcium chloride solution are required to react with 120 mL of 15 M phosphoric acid solution? CaCl2 + H3PO4 → Ca3(PO4)2 + HCl
@Whitemonsterbunny17
I'm sorry, I don't know chemistry... :s But I can help with English, Biology, History, Design, and some Economics... c:
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Sorry dont know this but I think he can help you -> @mrdoldum
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He's working with a question.
OH
@CrazyTown~JA
I am not taking chemistry till next year so I can't help sorry
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@douglaswinslowcooper
Tanya, first you need to write a balanced equation for the reaction, a CaCl2 + b H3PO4 ---> c Ca3(PO4)2 + d HCl must find a,b,c,d if c =1, then a is probably 3 to get the Ca balanced on both sides so we try 3 CaCl2 + b H3PO4 ---> 1 Ca3(PO4)2 + d HCl that means d = 6 to get the Cl balanced on both sides 3 CaCl2 + b H3PO4 ---> 1 Ca3(PO4)2 + 6 HCl and b =2 to balance the H on both sides and the (PO4) 3 CaCl2 + 2 H3PO4 ---> 1 Ca3(PO4)2 + 6 HCl check to see have the right count: 3 Ca, 6 Cl, 6 H, 2 PO4, check You need 2 moles of phosphoric acid [H3PO4] for every 3 moles of CaCl2. How many moles of phosphoric acid are in 120 ml of 15 M? Doesn't M stand for moles/liter? If so, then this is [120ml][15moles/1000ml] = 1.8 moles. the ratio of phosphoric / calcium chloride needed = 2/3 so, you have (5.4 moles/liter) CaCl2 in your solution. Figure out how much of this solution you need to get (3/2)(1.8 moles)=2.7 moles Ca to balance the phosphoric acid
Thank you very much @douglaswinslowcooper Outstanding job !!!! and thanks for the testimonial =')
You are vey welcome!
I'm still confused
What part puzzles you?
the explanation srry I'm not good at chem
@BMasterOB123
Try to ask a specific question about a part of the explanation that is unclear to you.
the whole thing i understand better when someone explains step by step
@lonnie455rich
I dont think there is any better way to explain it other than the way douglas did. At least i cant. sorry
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