May I please have some help? A medal and a fan will be given. :) The following function represents the profit P(n), in dollars, that a concert promoter makes by selling tickets for n dollars each: P(n) = -250n^2 + 2,500n - 4,000 Part A: What are the zeroes of the above function and what do they represent? Show your work. Part B: Find the maximum profit by completing the square of the function P(n). Show the steps of your work. Part C: What is the axis of symmetry of the function P(n)?
\[\Large\rm P(n)=-250n^2 + 2500n - 4000\]So the find `zeros`, we set the P(n) equal to zero.\[\Large\rm 0=-250n^2 + 2500n - 4000\]This will be easier to work with if we have no fancy coefficient on the squared term. So let's factor a -250 out of each term:\[\Large\rm 0=-250(n^2-10n+16)\]Then divide the -250 away,\[\Large\rm 0=n^2-10n+16\]It looks like this will factor nicely! Confused by any of those steps?
Hold on one second, let me look really quickly. :)
Nope! I understand for sure! So, I find the GCF for the 16?
Factors of 16 that add to -10. So we want two numbers that multiply to give us positive, but add to give us negative, So both factors should be negative. Can you find the right combination? :o
Yes, I can hehehehehe...give me 3 seconds.
\[-8 - 2 = - 10/ -8 • -2 = +16\]
So, \[0 = n^2 - 8n - 2n + 16\]
I'm alone again...I can't wait to get on the road again! :D
Mmmm ok if you're going to break it up like that, I guess we can factor by grouping.
I found my answer! Would you like to see the process?
\[n^2 - 8n\] \[n^2, n\] \[n ( n - 8 )\]
\[\Large\rm 0 = \color{royalblue}{n^2 - 8n} \color{orangered}{- 2n + 16}\]\[\Large\rm 0 = \color{royalblue}{n(n - 8)} \color{orangered}{- 2n + 16}\]k looks good so far,
\[-2n + 16\] \[-2: 2 • 1\] \[16: 8 • 2\] \[GCF: -2 ( n - 8 )\]
\[( n - 2 ) ( n - 8 )\]
Cool. so our zeros are what? n=?
Our zeroes, good sir/ma'am, are +2, and +8.
Mmm k cool :) What do you think these values might represent? Read this sentence again: The following function represents the profit `P(n)`, in dollars, that a concert promoter makes by selling tickets for `n` dollars each:
I think that they represent the amount of dollars the promoter earns from a concert per ticket sold?
That's the general representation of the function and n. That' doesn't answer part A though. So we set our P(n) equal to zero. So these are the specific ticket prices, `n`, which result in ZERO profit. Understand?
Oh, so they represent the specific prices, +2 and +8, which will result in a zero profit? Is that my answer with the work as well?
Yes, part A is that reponse + the work we did. 2$ wasn't a high enough price. We didn't charge enough, didn't make any profit. 8$ per ticket was too expensive, not enough people bought tickets or something.
Ooo we've gotta complete the square >.<
Ah yes Part B:....how I am going to not miss doing this. XD
Going back to our original expression:\[\Large\rm P(n)=\color{royalblue}{-250n^2 + 2500n} - 4000\]We want to complete the square on this blue part.
Ok
Again, factoring out a -250 gives us:\[\Large\rm P(n)=\color{royalblue}{-250(n^2 - 10n)} - 4000\]
The part inside the brackets, do you remember how to complete the square?
I think I'm supposed to distribute it, right?
You take half of the b term, and square it. That's the value that completes the square. So we have -10 and we need to cut it half and then square it.
OOOOohhhhhh.....I was doing this earlier, and I never understood what to do next.
I remember this part, would you mind helping me with this? It's a little difficult with these numbers, hehe. ^^'
So half of -10 is -5. Then squaring it tells us that positive 25 is the value we want to complete the square, yes?
\[P (n) = −250 ( n^2 − 10n + 25 ) −4,000\]
Yes
\[\Large\rm P(n)=-250(n^2 - 10n\color{orangered}{+25}) - 4000\]Ok good. But do you see the mistake we made? In the land of math, we can't just add 25 willy nilly. We have to keep things balanced, yes?
Correct, we need to subtract 25 from both sides.
4,000 - 25 = 3,975
No no this is where we need to be very careful! We didn't add 25 to the right side. We added 25 inside the brackets yes? ( which results in a different number when taken out of the brackets) So we need to subtract 25 in the brackets as well.
\[\Large\rm P(n)=-250(n^2 - 10n+25-25) - 4000\]
Wait...then we do what I said above right? Then-wait. I got it. -4000 - 25. I forgot the negative sign on the 4,000. HA Algebra is a killer! XD
Our goal is to end up with only this blue part in the brackets:\[\Large\rm P(n)=-250(\color{royalblue}{n^2 - 10n+25}-25) - 4000\]Then we'll be able to write it as a perfect square. So we need to pull the -25 out of the brackets somehow.
Ok continue...
No when we pull the -25 out of the brackets, we have to multiply it by the -250 right?
So it turns into a very different number.
Right
Yeah, like over 5,000 I believe.
\[\Large\rm P(n)=-250(\color{royalblue}{n^2 - 10n+25})+6250 - 4000\]Yah, not quite over 9000 ;) but yes.
Haha! I got the 9,000 part! XD I understand what to do!
So, the answer would be:
\[P( n ) = -250 ( n^2 - 10n + 25 ) 2,250\]
\[P( n ) = -250 ( n^2 - 10n + 25 ) +2,250\]Ok good. Now we need to write the bracketed portion as a perfect square.
Could you show me?
@zepdrix
Well we could factor by grouping again if you're more comfortable with that.
Ok, let's do that!
\[\Large\rm n^2-10n+25\]
Do it!! >.<
brb i need some chocolate milk :U
Ok...it's good for you heart!
\[n^2 - 5n - 5n + 25\] \[n ( n - 5 )\] \[-5 ( n - 5 )\] \[( n - 5 )^2\]
Bum bum!
\[\Large\rm P( n ) = -250 (n-5)^2 +2,250\]Cool.
What shape does this function make?
Hold on, let me think...
A parabola?
Mmm ok good, and since the leading term is negative, it's opening downward right?
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