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OpenStudy (anonymous):
I'm doing it manually
ganeshie8 (ganeshie8):
wolfram has the correct quadratic formula format
look it up
OpenStudy (anonymous):
So I can't let x = pi x r ??
OpenStudy (anonymous):
No
ganeshie8 (ganeshie8):
\( \color{red}{2\pi} r^2+\color{red}{14\pi} r \color{red}{-231}=0\)
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ganeshie8 (ganeshie8):
why do you want to let x = pi x r ?
OpenStudy (anonymous):
So that it takes the quadratic form of ax^2 + bx + c
ganeshie8 (ganeshie8):
its already in the quadratic form :
\(\color{red}{2\pi} r^2+\color{red}{14\pi} r \color{red}{-231}=0 \)
\(a = \color{red}{2 \pi}\)
\(b = \color{red}{14 \pi}\)
\(c = \color{red}{-231}\)
ganeshie8 (ganeshie8):
And yes, \(\color{red}{\pi}\) is just a number
ganeshie8 (ganeshie8):
if u prefer, u may put \(x = r\)
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OpenStudy (anonymous):
Thank you for the explanation :)
ganeshie8 (ganeshie8):
np :)
OpenStudy (anonymous):
I have one more question
Where did 44/7 r^2 come from?
OpenStudy (anonymous):
I just multiplied it by 2.
OpenStudy (anonymous):
Could you please show me?
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OpenStudy (anonymous):
2(22/7)
2*22=44
44/7
OpenStudy (anonymous):
There ya go.
OpenStudy (anonymous):
And the 22/7?
OpenStudy (anonymous):
That's what pi represents as a fraction.
OpenStudy (anonymous):
Thank you
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