Question

hi

Answer 1

Just answered this for someone else.

280 = L W

L-5 = W+1

solve for L and W

2 eqns and 2 unkns ok

Answer 2

It is given that the width is x meters. Let the length be y meters. Using the given information we can write the following equation:
x + 1 = y -5 .............(1)
We also know that
xy = 280 ..................(2)
Now the value of x can be found by solving the simultaneous equations (1) and (2).

Answer 3

area=(width)(length) in this case area=xy since the area=280 square meters it turns into xy=280 square meters but since length is 5 times less and width is 1 times more its (y-5)(x+1)=280 square meters now try it see if this helps

Answer 4

LW = 280 so L = 280/W

thus [280/W - 5] = W + 1 multiply both sides by W

280 - 5W = W^2 + W

0 = W^2 + 6 W - 280

solve this quadratic equation for W, using standard formula for quadratic equations.

Answer 5

\[0 = W^2 + 6 W - 280\]is the same form as \[0 = ax^2+bx+c\]with \(a =1,~b=6,~c=-280\)

We can use the quadratic formula as we have our equation in the right form:

\[x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\](I've changed back to \(x\), but it makes no difference which letter you use, just remember that we are finding the value of W!)

\[W = x = \frac{-6\pm\sqrt{6^2-4(1)(-280)}}{2(1)} = \]