Show that sin x + 2x has exactly one solution. Calc! How do I do this? :/ Thank you! :)
did you mean sins + 2x = 0 ?
no... sin x + 2x
but that is not an equation, so it stays the same
wait i made a typo i mean sinx+2x=0
i think that's what it means haha it just says show that sin x + 2x has exactly one solution.... :/
because its linear? without it = to something who knows. you could assume its = to 0
ohh okay thank you!
By inspection \(x = 0\) is one solution Next, notice that the first derivative \(\cos x + 2\) is always positive \(\implies \) the given function is strictly increasing \(\implies \) it cuts the x axis only once. QED.
@ganeshie8 ohh okay... how do you show that it has exactly one solution (x=0) though?
sinx + 2x = 0 sinx = -2x sin(0)=0 2(0)=0
ohh so that's all that goes into it? using calc? :O
it cuts x-axis only once => it has exactly one and only one solution :)
oh, how would i be able to show the work for that? :/ would i use a graph or something? :O
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