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Mathematics 15 Online
OpenStudy (anonymous):

Show that sin x + 2x has exactly one solution. Calc! How do I do this? :/ Thank you! :)

OpenStudy (linyu):

did you mean sins + 2x = 0 ?

OpenStudy (anonymous):

no... sin x + 2x

OpenStudy (linyu):

but that is not an equation, so it stays the same

OpenStudy (linyu):

wait i made a typo i mean sinx+2x=0

OpenStudy (anonymous):

i think that's what it means haha it just says show that sin x + 2x has exactly one solution.... :/

OpenStudy (anonymous):

because its linear? without it = to something who knows. you could assume its = to 0

OpenStudy (anonymous):

ohh okay thank you!

ganeshie8 (ganeshie8):

By inspection \(x = 0\) is one solution Next, notice that the first derivative \(\cos x + 2\) is always positive \(\implies \) the given function is strictly increasing \(\implies \) it cuts the x axis only once. QED.

OpenStudy (anonymous):

@ganeshie8 ohh okay... how do you show that it has exactly one solution (x=0) though?

OpenStudy (linyu):

sinx + 2x = 0 sinx = -2x sin(0)=0 2(0)=0

OpenStudy (anonymous):

ohh so that's all that goes into it? using calc? :O

ganeshie8 (ganeshie8):

it cuts x-axis only once => it has exactly one and only one solution :)

OpenStudy (anonymous):

oh, how would i be able to show the work for that? :/ would i use a graph or something? :O

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