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Mathematics 22 Online
OpenStudy (anonymous):

Find the area of each regular polygon with the given radius or apothem. http://i85.photobucket.com/albums/k62/sbpll2012/73a09f49-d029-47c1-bc4d-d89b0ca4dd8c_zpsaf5ceaa6.png

OpenStudy (yttrium):

Just take note that \[A = a^2 N \tan \frac{ 180 }{ N }\] where N = number of sides a = measure of apothem

OpenStudy (yttrium):

Now, can you apply the formula?

OpenStudy (anonymous):

Would this be the first part? A = 6√3^2

OpenStudy (yttrium):

Yeah \[(6\sqrt{3})^2\] but you also need to put the other variables

OpenStudy (anonymous):

what about be N?

OpenStudy (yttrium):

N means number of sides.

OpenStudy (yttrium):

How many sides it has? @sbpll2014

OpenStudy (anonymous):

Oh it has 6. So it would be \[A = (6\sqrt{3})^{^{2}}6 \tan 180\div6\] ?

OpenStudy (yttrium):

Right. But let me show you the correct expression \[A = (6\sqrt{3})^2(6)\tan \frac{ 180 }{ 6 }\]

OpenStudy (anonymous):

and if we solve that we would get 162 √ 3 m^2

OpenStudy (yttrium):

are you sure of it?

OpenStudy (anonymous):

yes...

OpenStudy (anonymous):

or 36?

OpenStudy (yttrium):

Don't you know how to simplify expressions?

OpenStudy (yttrium):

Let me tell you how, then.

OpenStudy (yttrium):

(6sqrt(3))^2 is also 36(3) = 108

OpenStudy (yttrium):

Therefore, we have now 108(6) tan30

OpenStudy (yttrium):

648tan30 is the right answer. But I will be giving the turn to you to simplify this one.

OpenStudy (anonymous):

would it be simplified in a square root?

OpenStudy (yttrium):

Yup. I want you to give me the answer. :)

OpenStudy (anonymous):

216√ 3

OpenStudy (yttrium):

Now you got it right

OpenStudy (anonymous):

Thank you

OpenStudy (yttrium):

Np

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