Question

Indefinite Integral

Answer 1

u=x-2
du =dx

Answer 2

so many folks eager to help you :)

Answer 3

\[\int\limits_{}^{}\frac{ x }{ \sqrt{x+1} }\]

Answer 4

dx

Answer 5

u=x+1 hahahaa

Answer 6

yeah but then what?

Answer 7

du = dx

Answer 8

x =? :)

Answer 9

x = u-1

Answer 10

boom boom boom

Answer 11

boom got it :D

Answer 12

thx batman

Answer 13

\[\int\limits \frac{ u-1 }{ \sqrt{u} }du\]

Answer 14

Oh alright :)

Answer 15

thx everyone actually XOXO

Answer 16

What did you get as an answer?

Answer 17

dont ask, answer is something unpleasant i suppose ;)

Answer 18

And yw ;)

Answer 19

Not too bad :), I can show the steps if you want.

Answer 20

i got [2(x+1)^(5/2)]/5 - [2(x+1)^(3/2)]/3 + C

Answer 21

Not quite

Answer 22

wha?

Answer 23

i combined (u-1)(u)^1/2 before integrating

Answer 24

so u^3/2 -u^1/2

Answer 25

then i integrated that

Answer 26

and imported u = x+1 for it

Answer 27

u^(1/2) - u^(-1/2)

Answer 28

\[\int\limits \left( \sqrt{u}-\frac{ 1 }{ \sqrt{u} } \right)du\]

Answer 29

ahhh you're very right..

Answer 30

darn

Answer 31

:)

Answer 32

\[\huge \frac{ 2 }{ 3 }(x-2)\sqrt{x+1}+C\]

This should be your final answer.

Answer 33

thats what WFA gave me too.. but it still doesn't look like that >.<

Answer 34

\[\huge \int\limits \sqrt{u}du-\int\limits \frac{ 1 }{ \sqrt{u} }du\]

\[\huge \frac{ 2u ^{3/2} }{ 3 }-2\sqrt{u}+C\]

\[\huge \frac{ 2 }{ 3 }(x+1)^{3/2}-2\sqrt{x+1}+C\]

\[\Huge \frac{ 2 }{ 3 }(x-2)\sqrt{x+1}+C\]

Answer 35

Alright, I gtg now, good night and take care :).

Answer 36

GOT IT!