Is it TRUE or FALSE ? If a∈Q and b∉Q,then ab∉Q. Prove your choice.
false if b ='s ∉ then a*b can't =∉
s means
\(a = p/q\) and say \(ab \in \mathbb Q\), then : \(ab = p/q*b = u/v\) \(\implies b = (uq)/(vp)\) contradiction - QED.
Can you give me some example?
example : \(a = 2/3,~ b = \sqrt{2}\)
multiply them : \(ab = 2/3 * \sqrt{2} \not \in \mathbb Q\)
\(\text{rational} \times \text{irrational} = \text{irrational}\)
so this statement is true
Yep !
but in answer this statement is false
this is a trivial proof, so i wont argue : http://math.stackexchange.com/questions/45104/prove-that-the-product-of-a-rational-and-irrational-number-is-irrational
wait a sec, the given statement is FALSE when \(a = 0\) in all other cases it is TRUE
so your textbook answer is right : the counter example is : \(a = 0, ~~b = \sqrt{2}\) \(ab = 0*\sqrt{2} = 0 \in \mathbb Q\)
yeah....thank you so much
you're welcome !
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