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Mathematics 6 Online
OpenStudy (anonymous):

WILL FAN AND MEDAL Matt has $200 in his bank checking account. Each month he deposits $300 into his account. Matt is saving up for a used car that costs $4200. A. Look at the algebraic equations below. Which equation can be solved to find out the number of deposits Matt needs to accumulate more than $4200? (1 point) •200x + 300 > 4200. •300x + 200 > 4200. •200x + 300 < 4200. •300x + 200 < 4200. B. Solve, using algebraic transformations, the equation that you chose for Part A. C. How many deposits does Matt need to accaccumulate more than $4200? Remember labels.

OpenStudy (anonymous):

I need show work and I need it labeled A B C

OpenStudy (texaschic101):

correct....300x + 200 > 4200

OpenStudy (anonymous):

@texaschic101 I need show work did u read the question and I neeed it labeled Part A B C

OpenStudy (anonymous):

no @pinksparkles I mean thanks for the answer but I all the answers for part a b c

OpenStudy (texaschic101):

300x + 200 > 4200 -- subtract 200 from both sides (A) 300x > 4200 - 200 300x > 4000 -- divide by 300 on both sides (B) x > 4000/300 x > 13.33 -- gonna have to round it to 14 (C) check... 300(14) + 200 > 4200 4200 + 200 > 4200 4400 > 4200 (correct) Would have to make 14 payments, because 13 would not quite be enough I am not sure if the A,B, and C are in the correct place.

OpenStudy (texaschic101):

oh...I read it wrong A. 300x + 200 > 4200 B. I solved it above C. He would have to make 14 payments

OpenStudy (anonymous):

@texaschic101 can u relable the question were does a start and were does it end were does b start were does it end and the samething with see

OpenStudy (anonymous):

@texaschic101

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