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A particle with an initial velocity of 12 m/s has its acceleration modeled by the equation a(t) = t 2 + 3. Find the particle’s velocity at t = 2
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a(2) = (2)^2 + 3 solve
possible answers can only be 4 8.667 14.667 20.667
Yes. My fault. Sorry. Too early for me. v(t) = integral of acceleration v(t) = v(0) + (1/3) t^3 + 3t evaluated at t=2 v(2) = 12 + (8/3) + 6 = 20.667
thank you sooooooo much !! have a nice day !!
You are very welcome. Have a great day, too.
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