Question

Find the value of the variables in these matrices.

(Picture will be below)

Answer 1

\[\left[\begin{matrix}\color{blue}{ \bf A } & \color{green}{ \bf B } \\ \color{red}{ \bf C } & \color{purple}{ \bf D } \end{matrix}\right]=\left[\begin{matrix}\color{blue}{ \bf E } & \color{green}{ \bf F } \\ \color{red}{ \bf G } & \color{purple}{ \bf H } \end{matrix}\right] \]

Answer 2

All same colors are equal, like A=E and so on....

Answer 3

that's the RULE .

Answer 4

Ahh okay that makes sense. Then what do we do? @SolomonZelman

Answer 5

OK< look at your equations, what can you conclude?

Which things are equals of each other in your example (look at the matrix I posted above to see the concept and then look at your attachment).

Answer 6

@SolomonZelman

Answer 7

Yes, CORRECT !! So looking at the first two equations you have written out,

\(\LARGE\color{orangered}{ \bf -12 = 2k }\)

\(\LARGE\color{brown}{ \bf -w^2 = -81 }\)


can you solve for k in the first one, and for w in the second one ?

Answer 8

you are correct for the K.

Answer 9

your mistake is that, \(\LARGE\color{red}{ \bf -w^{2}≠(-w)^{2} }\)

Answer 10

Ahh whoops. So then what? Is that all there is?? @SolomonZelman

Answer 11

Well, you had an equation of

\(\LARGE\color{forestgreen}{ \scr -w^2 = -81 }\) to give you a better conceptual clue, will re-write it in a different, but equivalent way.

\(\LARGE\color{forestgreen}{ \scr (-1)\times w^2 = (-1)\times 81 }\)

Answer 12

Ahh that makes sense. Thanks for the help!

Answer 13

\(\LARGE\color{forestgreen}{ \tt anytime ~! }\)