Solve for x a) 8^5 =32^3x
3x is the exponent, right ?
yes
\(\LARGE\color{blue}{ \bf 8^5 =32^{3x} }\) \(\LARGE\color{blue}{ \bf (2^{3})^5 =32^{3x} }\) \(\LARGE\color{blue}{ \bf (2^5)^{3} =32^{3x} }\) \(\LARGE\color{blue}{ \bf 32^{3} =32^{3x} }\) can you do it now ?
I really though the logarithms were necessary, but oh well....
how would i solve for x
If you do not know how to solve for x after I (not even "pretty much, but JUST) just gave you the answer, then no matter how I am sorry to say this, but I really can't help you -:(
I am giving you a chance. \(\LARGE\color{blue}{ \bf 2^{3}=2^{b} }\) THEREFORE \(\LARGE\color{blue}{ \bf 3=b }\)
so i add the 3's that would make x = 6
No, lost case, I am out from here !
ok
I would teach you, but you are probably not willing.
i am
OK
You will need to be engaging a lot, to show the willingness. \(\LARGE\color{blue}{ \bf 9=9 }\) right? got it? Now, \(\LARGE\color{blue}{ \bf 9=3^{2} }\) correct ?
yes i understand that
\(\LARGE\color{blue}{ \bf 3^{2}=3^{2} }\) correct?
ya they are the same
\(\LARGE\color{blue}{ \bf 3^{b}=3^{2} }\) these THREEs have to have equal exponenets to be equal to each other, so therefore we can conclude that \(\LARGE\color{blue}{ \bf b=2 }\) RIGHT ?
yes
\(\LARGE\color{blue}{ \bf 32^{3}=32^{3x}~~~. }\) What can you say about this ?
something has to equal to 32^3
we sub in a number for x
the THIRTY-TWOs have to be equal to each other, and so do their exponents.
ok 32^3(1)
the number wont change because the 1
yes, so x= ?
x= 32768
am i right?
OMG, I am stopping this question, even though I am not a moderator !!! \(\normalsize\color{black}{ \bf ▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄ }\)
why?
Because you need to talk to your teacher, and get help from a teacher or a special tutor. And I am not joking, this is very very serious !!
ok
Yes, please do... for your own sake.
ok
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