So we have the 2 points...
(1 , 1) and (-6 , 8)
(x1,y1) (x2 , y2)
So we plug those into the equation
\[\large slope =\frac{8 - 1}{-6 - 1} = \frac{7}{-7} = ?\]
OpenStudy (anonymous):
-1
OpenStudy (anonymous):
thank you!
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OpenStudy (johnweldon1993):
Anytime :)
OpenStudy (anonymous):
@johnweldon1993
OpenStudy (johnweldon1993):
When we have an infinite slope (vertical line) we have an undefined slope
OpenStudy (johnweldon1993):
|dw:1399503110911:dw|
OpenStudy (anonymous):
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OpenStudy (anonymous):
Negative uh?
OpenStudy (johnweldon1993):
|dw:1399503199759:dw|
so yes negative :)
OpenStudy (anonymous):
Thank you!
OpenStudy (anonymous):
@johnweldon1993
OpenStudy (anonymous):
it gon be positive right
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OpenStudy (johnweldon1993):
Perpendicular lines have negative reciprocal slopes
Meaning...if you multiply the slopes of both the lines...it should be - 1
And yes it will be positive
OpenStudy (johnweldon1993):
Lol ...so in this case...
negative reciprocal means flip the number...and then turn it negative (or change the sign)
-5 will become -1/5
And negative would mean it is then 1/5
OpenStudy (anonymous):
OpenStudy (johnweldon1993):
So if the slope of that green one is -8
We will need the negative reciprocal of that....
so flip the number \[\large -8 = -\frac{8}{1} \rightarrow -\frac{1}{8}\]
And change the sign of it... \(\large \frac{1}{8}\)
OpenStudy (anonymous):
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OpenStudy (johnweldon1993):
Parallel lines = same slope :)
OpenStudy (anonymous):
why you so smart_______- lol
OpenStudy (anonymous):
OpenStudy (johnweldon1993):
Lol idk :P and same thing here...same slope = parallel
OpenStudy (anonymous):
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