Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Help

OpenStudy (anonymous):

OpenStudy (johnweldon1993):

2 points \[\large slope = \frac{y_2 - y_1}{x_2 - x_1}\]

OpenStudy (johnweldon1993):

So we have the 2 points... (1 , 1) and (-6 , 8) (x1,y1) (x2 , y2) So we plug those into the equation \[\large slope =\frac{8 - 1}{-6 - 1} = \frac{7}{-7} = ?\]

OpenStudy (anonymous):

-1

OpenStudy (anonymous):

thank you!

OpenStudy (johnweldon1993):

Anytime :)

OpenStudy (anonymous):

@johnweldon1993

OpenStudy (johnweldon1993):

When we have an infinite slope (vertical line) we have an undefined slope

OpenStudy (johnweldon1993):

|dw:1399503110911:dw|

OpenStudy (anonymous):

OpenStudy (anonymous):

Negative uh?

OpenStudy (johnweldon1993):

|dw:1399503199759:dw| so yes negative :)

OpenStudy (anonymous):

Thank you!

OpenStudy (anonymous):

@johnweldon1993

OpenStudy (anonymous):

it gon be positive right

OpenStudy (johnweldon1993):

Perpendicular lines have negative reciprocal slopes Meaning...if you multiply the slopes of both the lines...it should be - 1 And yes it will be positive

OpenStudy (johnweldon1993):

Lol ...so in this case... negative reciprocal means flip the number...and then turn it negative (or change the sign) -5 will become -1/5 And negative would mean it is then 1/5

OpenStudy (anonymous):

OpenStudy (johnweldon1993):

So if the slope of that green one is -8 We will need the negative reciprocal of that.... so flip the number \[\large -8 = -\frac{8}{1} \rightarrow -\frac{1}{8}\] And change the sign of it... \(\large \frac{1}{8}\)

OpenStudy (anonymous):

OpenStudy (johnweldon1993):

Parallel lines = same slope :)

OpenStudy (anonymous):

why you so smart_______- lol

OpenStudy (anonymous):

OpenStudy (johnweldon1993):

Lol idk :P and same thing here...same slope = parallel

OpenStudy (anonymous):

OpenStudy (johnweldon1993):

Its a vertical line again..so undefined :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!