Put the following radical expression into simplified form. Assume all variables represent positive numbers.
\[\sqrt{\frac{ 48x^2y^3 }{ 5 }}\]
@iambatman
\[\sqrt{48}=4\sqrt{3}\] x is now outside of the radical & so is on y & y^2 is inside the radical? & the 5 just syas there?
*one
\[\frac{ 4xy \sqrt{3y} }{ 5 }?\]
@mathslover
Well done @cookiibabii93
Thank you ! :)
@Jack1 , this one too...Sorry to work you, but this is for a quiz lol i need all these points
\[\large \sqrt{\frac {48 x^2 y^2} 5}\] \[\large \sqrt{\frac {48 x^2 y^2} 5}\] \[\large \sqrt{\frac {48}{5} {x^2 y^2}}\] \[\large \sqrt{\frac {48}{5}} \times \sqrt{x^2} \times\sqrt{ y^2}\] \[\large \sqrt{\frac {48}{5}} \times x \times y\]
So, I dont factor the 48?
wait, is that a y^3 or y^2 ...?
y^3
gotcha, then \[\huge 4 \sqrt \frac 35 \times x \times y^{\frac 32}\]
that's the answer?! lol
yeahs, just an extra step and i had to change the power on the y
Is it all under the radical?
nah, only the fraction is x becomes 2/2 so to the power of 1 y becomes 3/2, so you can see that's still there 4 is extracted out
Oooooh ok, thanks...one more lol
k but i gotta go soon
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