Question

Just need someone to check my answers to make sure I'm on the right track

y=x^2+8x-14
is a....
Parabola. Form y=(x+4)^2 + 30
Vertex (-4,-30)

x^2=12+4y^2-8y
is a...
Hyperbola. Form x^2/8 - (y-1)^2 /2 =1
Center (0,1)

Answer 1

I know I identified the problems correctly as Parabola, Ellipse, Circle, etc... just the part that said "Form" and had a blank confused me

Answer 2

#1 (x+4)^2 + 30 = x^2 + 8x + 16 + 30 = x^2 + 8x + 46

Seems like something went wrong, there. Try Completing the Square, again.

Answer 3

for instance, \[4x ^{2} -16x = -9y ^{2} -18y + 11\] is an Ellipse, right?

How am I supposed to get this into Ellipse form

Answer 4

Checking #1 right now... I checked it on Mathway. Not sure how that happened

Answer 5

Looks like #2 is good! Good work.

Answer 6

I checked #1 on Mathway, clicked "Find Vertex form" and it came up y=(x+4)^2 - 30. Put PLUS instead of MINUS 30. Does that make it correct?

Answer 7

You tell me. We had -14. We added 16. We should correct with another -16.

-14 - 16 = ??

Answer 8

30! Ok, that makes sense! Could you help me on that 3rd one I wrote above? The Ellipse

Answer 9

Nevermind, I think I got it! It's \[\frac{ (x-2)^{2} }{ 9 }+\frac{ (y-1)^{2} }{ 4}=1\]