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sec(theta/4)=sqrt2
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\[\sec (\frac{ \Theta }{ 4 })=\sqrt{2}\]
@Miracrown
Use the relation sec(x) = 1/cos(x).
can you show me how to do it please
hello? @shiraz14
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Let x=θ/4. Then we have: sec(θ/4) = 1/[cos(θ/4)] = √2 => cos(θ/4) = 1/(√2) Now, consider the following diagram: |dw:1399539100812:dw| This is a special isosceles triangle where θ/4 = 45 deg => θ=180 deg So the general solution of θ is θ=180+2n(360) deg. or θ=(π+2nπ) rads.
so whats the answer pi+2npi?
@brucek69 : Yes, that's correct (if you want the answer in radians). I should modify the triangle a little as follows: |dw:1399539416211:dw|
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