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Mathematics 12 Online
OpenStudy (anonymous):

help for real

OpenStudy (anonymous):

OpenStudy (anonymous):

What could be a possible value for x? A. 3.5 B. 4.0 C. 4.5 D. 5.5

OpenStudy (twopointinfinity):

if you switch the L and the O in mathslover's name it says mathsolver.

mathslover (mathslover):

Let us first consider two triangles : ABZ and BCZ In Triangle ABZ : AB + AZ > BZ So, 8.8 + 4.79 > BZ => 13.59 > BZ Now, in Triangle BCZ : BC + CZ > BZ 4.79 + (2x+1) > BZ or 5.79 + 2x > BZ Now, as BZ is smaller than 13.59 ... So, 5.79 + 2x should also be greater than 13.59 so that BCZ triangle is possible.

mathslover (mathslover):

5.79 + 2x > 13.59 2x > 7.8 or x > 3.9

mathslover (mathslover):

@RobertoTB - Sorry brother, we're not here to just give out answers. We're here to help you with your problem and make you understand the basic concepts.

OpenStudy (anonymous):

so give the equation so i can solve it

OpenStudy (anonymous):

so what do i do with 3.9

mathslover (mathslover):

See, x has to be greater than 3.9 in order to have the figure possible.

mathslover (mathslover):

What can you conclude from the above point? Which option do you think will not be suitable for "x" ?

OpenStudy (anonymous):

2x+1>3.9 like that

mathslover (mathslover):

Oh oka, wait.

mathslover (mathslover):

*okay

mathslover (mathslover):

I think, I did a mistake there.

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

lol can you help me out

OpenStudy (anonymous):

us

mathslover (mathslover):

I think, I did mistake there in the inequality sign..

hartnn (hartnn):

yes just one 2x+1<8.8

mathslover (mathslover):

^

OpenStudy (anonymous):

What could be a possible value for x? A. 3.5 B. 4.0 C. 4.5 D. 5.5

mathslover (mathslover):

@RobertoTB - solve for x in : 2x + 1 < 8.8

OpenStudy (anonymous):

3.9

OpenStudy (anonymous):

so its B

mathslover (mathslover):

x < 3.9 means : x should be lesser than 3.9 Which option do you think, is lesser than 3.9 ?

OpenStudy (anonymous):

3.5

mathslover (mathslover):

Yes, so, that's your answer.

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