integral help
first or second?
both
Hello
the first one is a straight up calculator exercise compute \[f(1)+f(2)+f(3)+f(4)\]
I'm pretty sure that you can mange the very first problem on your own, right?
you are also supposed to multiply by \(\Delta x\) but since the distance between each of these numbers is 1, \(\Delta x=1\) so you can ignore that part
Definite integral is defined as following:\[\int\limits_{a}^{b}f(x)dx=\lim_{n \rightarrow \infty}\sum_{k=1}^{n}f(x _{k}) \Delta x\].
In which \[x _{k}=a+\frac{ b-a }{ n }k\]
Do you know what this means?
nope
You've heard of it, though, right?
ok.
do you know what does definite integral do?
you have to be honest. do you know it or not?
nope
I'll briefly inform you of what the heck definite integral does.
In short, it lets you find the "area" under a graph in an interval.
The reason I wrote "area" is because if the graph is below the x-axis, then the definite integral turns out to be negative.
But for this problem, the graph is over the x-axis in the interval [0,4], so we don't have to worry about the negative.
Here is a drawing that expresses what I said.
Are you familiar with the definite integral notation?
k, i understand what you just said
a little bit
Good! From what I said, if you understand the drawing from the link, then we're good to go to the next step.
kk
Great. Then, we'll move on to Riemann Sum.
A mathematician named Riemann (German) developed this method, called Riemann Sum, to calculate the definite integral.
okok
Do you remember the equation that I first gave you?
It looked like this: http://classconnection.s3.amazonaws.com/33333/flashcards/644875/jpg/area-sigma-notation-a.jpg
I just added that \[x _{i}=a+\frac{ b-a }{ n }i\]
You might get confused. I first used k, then I used i. They're basically the same, so you can ignore that little difference
but where does your RHS of your xi come from?
I'll explain it in a minute.
First, look at this drawing carefully. http://sy48497.tripod.com/artifacts/webquest/maple/images/rsintro2.gif
Let's say that I want to find the area under curve of a random function from 0 to 10 using Riemann Sum.
The method of Riemann Sum is show in the drawing; you add up rectangles that are under the graph.
yeh k
For all of the rectangles, the width is the same. We can say that the width of one rectangle is the change of x, or \[\Delta x\]
yep
For this particular graph, the definite integral started from 0, right?
Now, this is where some imagination and thinking come into play. Assume that under the graph, there are 'n' rectangles, ok?
yes it did. yeh k.
Now if n gets very very very close to infinity, what would happen to its width?
become very small?
Correct!
And at the same time, if you think about it, the sum of the rectangles would be almost the same as the area under the curve, right?
yes
Now, it might get a little complicated, so watch carefully.
From a to b, there are 'n' rectangles, so we can say that the width of one rectangle is \[\frac{ b-a }{ n }\], which is \[\Delta x\]
And, xi can be expressed in terms of Delta x as following \[x _{i}=a+\Delta x i=a+\frac{ b-a }{ n }i\]
Is there anything that you're confused on so far?
Hey
Can I ask you something?
For (b), is it asking to write the notation for definite integral, or actually calculate it?
If it is asking you to just write the notation, write\[\int\limits_{0}^{4}(2x+4)dx\] which means the "area" under the curve, y=2x+4, in the interval from 0 to 4
If it is asking you to actually calculate it, then watch these videos to apply the method to the problem; https://www.khanacademy.org/math/integral-calculus/indefinite-definite-integrals/riemann-sums/v/simple-riemann-approximation-using-rectangles I'm truly sorry for not being able to help you, but I'm in Korea, which means that it's 11:50, so I have to sleep for school tomorrow. Good luck!
k thanks anyway
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