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Chemistry 19 Online
OpenStudy (anonymous):

Help balancing an equation?

OpenStudy (anonymous):

OpenStudy (anonymous):

\[\color{green}{\text{HNO}_{3~(aq)} + \text{KOH}_{(aq)} \longrightarrow \text{KNO}_{3~(aq)} + \text{H}_2\text{O}_{(l)}}\]

OpenStudy (anonymous):

so what would the molar ratio of the acid to base be? How do you know?

OpenStudy (anonymous):

and how did you get that equation? I really want to understand this

OpenStudy (anonymous):

It is a double displacement reaction (an acid-base neutralization in this case). The anions and cations trade partners. The acid and base react in a 1 : 1 ratio, based on the mole ratio in the balanced chemical equation.

OpenStudy (anonymous):

You discover an unlabeled solution of Mg(OH)2 on your work bench and decide to use a solution of 1.25 M HCl for your titration process. You placed 35 mL of Mg(OH)2 into the flask and used 15 mL of HCl from the buret to complete the titration. so then for this question the equation would be Mg(OH)2 + HCl = H2O + MgCl2?

OpenStudy (anonymous):

or is that wrong?

OpenStudy (anonymous):

Balance the equation: \[\color{green}{ \text{Mg(OH)}_{2~(aq)} + 2\text{HCl}_{(aq)} \rightarrow 2\text{H}_2\text{O}_{(l)} + \text{MgCl}_{2(aq)} } \]

OpenStudy (anonymous):

how did you get 2HCl?

OpenStudy (anonymous):

this is what it looks like (it might be easier to read this way)

OpenStudy (anonymous):

You need to balance the equation so that the number of atoms shown on both sides of the equation are the same. This has to be done to satisfy the law of conservartion of mass.

OpenStudy (anonymous):

what would the molar ratio be and how do you know?

OpenStudy (anonymous):

The mole ratio is the same as the ratio of the coefficients in the balanced equation.

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