Help me relearn something please...Electric force due to half circle of radius 'R'
Find the electric Field due to a half circle of radius R and total charge Q. First estimate by dividing the charge into 5 equal parts...then repeat for 9 equal parts...and finally using integral calc to solve exactly.
I'm not sure if they mean at the center of said circle...or at some general point (not specific)...and I'm just having some serious mental blocks on how I used to do these...
No diagram came accompanying the question...but here's mine |dw:1399560376459:dw|
Hi
Coulomb's Law tells us the force between two point charges. Our variation tells us the Electric field due to a single point charge. What do we do if we have a continuous charge distribution? We can sum up the electric field caused by each tiny, infinitesimal part of the charge distribution. This means an integral over the charge distribution:\[e=kq/r2\] does that help at all
Yeah I know Coulombs Law... So basically when I break it up into 5 equal parts... Q = Q/5 |dw:1399561107134:dw| For sake of simplicity lets call those even lol... Lets move from there...
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