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Physics 8 Online
OpenStudy (johnweldon1993):

Help me relearn something please...Electric force due to half circle of radius 'R'

OpenStudy (johnweldon1993):

Find the electric Field due to a half circle of radius R and total charge Q. First estimate by dividing the charge into 5 equal parts...then repeat for 9 equal parts...and finally using integral calc to solve exactly.

OpenStudy (johnweldon1993):

I'm not sure if they mean at the center of said circle...or at some general point (not specific)...and I'm just having some serious mental blocks on how I used to do these...

OpenStudy (johnweldon1993):

No diagram came accompanying the question...but here's mine |dw:1399560376459:dw|

OpenStudy (anonymous):

Hi

OpenStudy (anonymous):

Coulomb's Law tells us the force between two point charges. Our variation tells us the Electric field due to a single point charge. What do we do if we have a continuous charge distribution? We can sum up the electric field caused by each tiny, infinitesimal part of the charge distribution. This means an integral over the charge distribution:\[e=kq/r2\] does that help at all

OpenStudy (johnweldon1993):

Yeah I know Coulombs Law... So basically when I break it up into 5 equal parts... Q = Q/5 |dw:1399561107134:dw| For sake of simplicity lets call those even lol... Lets move from there...

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