Question

@mathmale

Answer 1

Simplify: (4a – 2b)(a + b)



A.


4a2 – 2ab – 2b2


B.


4a2 – 8ab – 2b2


C.


4a2– 6ab – 2b2


D.


4a2 + 2ab – 2b2

Answer 2

Hey, you do look familiar. I'd like to pose a question for you: What would happen if you were to factor the 2 out of the first multiplicand and then multiply the two remaining binomial factors together? Personally, I'd think that approach would be a bit easier.

Answer 3

Note: (x-a)^2 is regarded as a "special product," because the product is easily memorized and applied to similar problems involving the square of a binomail.

Answer 4

OK, what should I do first?

Answer 5

What should you do first? Accept my apology. I assumed you had (4a+2b)(a+b). (Do you?)
In that case, the advise I gave you was just fine. But if you actually meant (4a-2b)(a+b), then I was "all wet." Before we move on, let's clarify which expression you wanted to work on, the one with first factor (4a-2b) or that with first factor (4a+2b).

Answer 6

I guess we should work on the first one...

Answer 7

Mr.Mathmale we should wait until after the update

Answer 8

If we focus on (4a+2b)(a+b), then the first thing I'd suggest would be that we factor the 2 out of the first factor. That results in 2(a+b)(a+b).

(a+b)(a+b) is a "special product" (because the two factors are identical). Remember the formula for (a+b)(a+b)?

I'd be glad to continue with this now or to wait until you feel ready. :)

Answer 9

I only said wait because OpenStudy is Lagging pretty badly so that's why I said wait

Answer 10

OK! Just tag me when you're ready to resume this conversation. Looking forward to that.

Answer 11

Ok Mr.Goldmann

Answer 12

'Til later, then! Bye.

Answer 13

See ya

Answer 14

@mathmale