Ethylene glycol (C2H6O2) is used as an antifreeze in cars. If 400 g of ethylene glycol is added to 4.00 kg of water, what is the molality? Calculate how much the freezing point of water will be lowered. The freezing-point depression constant for water is Kf = –1.86°C/m.

Question

anonymous · Answer

molar mass of ethylene glycol = 62g
mass of ethylene glycol = 400g
mass of solvent (in kg) = 4kg

molality = 
400/(62∗4)

=1.61m


delta Tf = Kf * m
= -1.81 * 1.61
= -2.99 C