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Lucas recorded his lunch expenditure each day for one week in the table below.Find the mean, standard deviation, and variance of Lucas’ lunch expenditures. Round to the nearest thousandth. (3 points) Sun Mon Tues Wed Thurs Fri Sat Expend. $4.85$5.10$5.50$4.75$4.50$5.00$6.00
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I know the mean is 5.1, I think the standard deviation is 0.218 but I'm not completely sure.
The mean of 5.1 is correct
If you're talking about the population variance, then the answer is indeed 0.218 Take the square root of this to get sqrt(0.218) = 0.4669047 and that rounds to 0.467
So the population variance is 0.218 The population standard deviation is 0.467
Thank you
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