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What is the current in a series circuit that has two resistors (4.0 ohms and 7.5 ohms) and a power source of 9.0 volts?
When resistors are in series, their effective resistance is:\[R _{eff}=R _{1}+R _{2}\]. Current is given by Ohm's Law:\[I=\frac{ V }{ R }\]where I is current; V is voltage; and R is resistance.
Do you see how to solve the problem now?
i have options of 2.6 amps 12 amps 1.6 amps 0.78 amps
You can use the two formulas I gave you to find the answer.
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i get .3
never mind i get .78 thanks a million
That's correct, and you're welcome.
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