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Mathematics 9 Online
OpenStudy (anonymous):

state how many complex and real zeros the function has.. f(x) = x^2 + 8x - 7

OpenStudy (wolf1728):

Use the quadratic formula to find the solutions. This has no complex solutions and the two solutions it has are both real.

OpenStudy (anonymous):

on my paper there are only 4 options A. 2 complex no real B. 2 complex 1 real C. 2 complex both real D. 4 complex 2 real @wolf1728

OpenStudy (wolf1728):

Wow I only know there are 2 solutions both real.

OpenStudy (anonymous):

cloey, what's the discriminant (b^2 - 4ac) , if it's a positive value or zero, then the answers are REAL, else Complex

OpenStudy (wolf1728):

Here is a quadratic equation calculator: http://www.1728.org/quadratc.htm It shows two solutions x = 0.79583 x = -8.7958 both are real. neither are complex

OpenStudy (wolf1728):

Some of those answers seem ridiculous: C: 2 complex both real What is that supposed to mean?

OpenStudy (anonymous):

i don't know... I'm pretty sure my instructor is insane... but thank you! @wolf1728 @kx2bay it's 36, that's what I got

OpenStudy (wolf1728):

It's like saying the equation has 2 odd solutions - both numbers are even

OpenStudy (anonymous):

she taught us that all complex numbers are real numbers @wolf1728

OpenStudy (wolf1728):

look up the definition of complex number - wait a minute - I'll look it up.

zepdrix (zepdrix):

complex numbers can have a real `components` but they are not real altogether.... what is this shinanigans?

OpenStudy (anonymous):

cloey its not 36 but rather 92, remember that c = -7 and -4ac = +28 ;)

OpenStudy (wolf1728):

I found this at dictionary.com complex number - a mathematical expression ( a + bi ) in which a and b are real numbers and i² = −1. Notice it does NOT say all the numbers are real.

zepdrix (zepdrix):

I ended up with:\[\Large\rm x=-4\pm \sqrt{23}\]Which are two `real numbers`. Option C seems to be the only one close. I think maybe your teacher doesn't know what complex means. Or there was a typo in the question.

OpenStudy (anonymous):

@zepdrix basically my teacher is somewhat insane and telling me that all complex numbers are real numbers. @kx2bay okay but... where on earth do i go from there? @wolf1728 i have no idea what to say other than : there's a reason she got fired this year

zepdrix (zepdrix):

lolol oh boy XD

OpenStudy (anonymous):

@zepdrix thank you! but... just use the quadratic essentially?

zepdrix (zepdrix):

ya quadratic should get you there c:

OpenStudy (anonymous):

thank you c: @zepdrix

OpenStudy (anonymous):

yes the answer is C your teacher is correct although bit in sane the "i" part of the Complex number, i.e. the Imaginary part is Zero when you have a Real number

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