Question

math help

Answer 1

the common ratio is \(r=\frac{1}{3}\)
is that much clear? because if so, then the answer is easy to get, you can pretty much do it in your head

Answer 2

if the answer is "no" i can explain how i know that \(r=\frac{1}{3}\)
i was just asking

Answer 3

the sum of the series is 1/3?

Answer 4

or do i add them up which comes to 1.4

Answer 5

oh no, that is not the sum
we are not there yet

Answer 6

hold on lets go slow

Answer 7

ohh

Answer 8

ok

Answer 9

in a geometric series, you multiply one number by \(r\) to get the next number, same \(r\) each time
since the first number is \(1\) and the second number is \(\frac{1}{3}\) it should be pretty clear that
\[r=\frac{1}{3}\] that is not the sum
that is just the "common ratio"

Answer 10

ok

Answer 11

now our job it to add all that stuff up
the ... out at the end means you are adding up an infinite number of numbers

Answer 12

the easy formula for this is
\[\frac{a}{1-r}\] where \(a\) is the first number you see
in this case \(a=1\) and \(r=\frac{1}{3}\)so our job is to compute
\[\frac{1}{1-\frac{1}{3}}\] which as i said above you can do in your head

Answer 13

think like this:
one minus one third is two thirds, and the reciprocal of two thirds (flip it) is three halves

Answer 14

in math it looks harder
\[\frac{1}{1-\frac{1}{3}}=\frac{1}{\frac{2}{3}}=\frac{3}{2}\]

Answer 15

i see... ok

is that all, or is there more to do

Answer 16

done
finished
stick a fork in it
halas

Answer 17

ok....thanks...