Question

need help

Answer 1

\[\huge \int\limits_{}^{}\frac{ 3 }{ (2-x)^{2} }dx\]

Answer 2

Pull the 3 out, u = 2-x, du = -dx you'll get 1/u^2du ..etc.etc, gtg now, take care and good night! :)

Answer 3

@satellite73

Answer 4

@sourwing

Answer 5

\[u=2-x,du=-dx\] should get it in one step

Answer 6

Yes i got that

Answer 7

\[-3\int \frac{du}{u^2}\] etc

Answer 8

after that

Answer 9

\[\frac{1}{u^2}=u^{-2}\]power rule backwards