Question

6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days.

Answer 1

6m+8w=10-->1
26m+48w=2-->2

*eqn 1 into 6 so 36m+48w=60
eqn2 26m+48w=2
m=5.8 ,w=3.1

Answer 2

Not exactly the way to solve this problem. The approach will be different.

Answer 3

Let us take some common variables to represent the work done by man and woman in 1 day :

Work done by 1 man in 1 day : x

Work done by 1 woman in 1 day : y

Answer 4

So, we can say, that

Work done by 6 men in 1 day : 6x

Work done by 8 women in 1 day : 8y

It is given that 6 men and 8 women complete the work in 10 days .

So, 6 men and 8 women will do 1/10 of the total work in 1 day, right?

Answer 5

yes that i used before then

Answer 6

Not exactly. The process you did had a mistake in RHS

it should be 1/10 in the first equation in RHS :

\(\boxed{\mathsf{ 6x + 8y = \dfrac{1}{10} \quad ------ (1) \\
26x + 48y = \dfrac{1}{2} \quad ----- (2) \\ }}\)

Answer 7

Solve these two equations for x and y and put them into

15 x + 20 y = ?

The answer you'll get will be 15 men's and 20 women's 1 day work. Just reciprocal the fraction obtained and you'll get your answer.

Good Luck

Answer 8

x=1/10 ,y=59/80

Answer 9

not yet

Answer 10

Not correct, which method did you use to solve these two equations?

Answer 11

36x+48y=6/10
26x+48y=1/2

Answer 12

x=1

Answer 13

6+8y=1/10

Answer 14

Okay fine :

\(\boxed{\mathsf{\color{blue}{36 x + 48 y = \dfrac{6}{10} \\
26x + 48 y = \dfrac{1}{2} \\
- \quad - \quad \quad - \\
10 x + 0 = \dfrac{6}{10 } - \dfrac{1}{2} \\
10x = \dfrac{6 - 5}{10} \\
10x = \dfrac{1}{10} \\
}} \color{red}{ \textbf{Divide 10 both sides}} \\
\color{blue}{ \mathsf{\dfrac{10x}{10} = \dfrac{1}{10 \times 10 } \\
\dfrac{\cancel{10} x}{\cancel{10}} = \dfrac{1}{100} \\
x = \dfrac{1}{100} }}}\)