A sequence has its first term equal to 8 and each term of the sequence is obtained by adding 6 to the previous term. If f(n) represents the nth term of the sequence, which of the following recursive functions best defines this sequence? f(1) = 6 and f(n) = f(n - 1) + 8; n > 1 f(1) = 8 and f(n) = f(n - 1) + 6; n > 1 f(1) = 8 and f(n) = f(n - 1) + 6n; n > 1 f(1) = 6 and f(n) = f(n - 1) + 8n; n > 1
A sequence has its first term equal to 8 can you rule out any of the 4 choices ?
im thinking the third one
Hopefully it is clear that A sequence has its first term equal to 8 means f(1)=8 so the first and last choices are definitely out.
each term of the sequence is obtained by adding 6 to the previous term. we can list a few terms, to see what the sequence looks like. It starts at 8 8 and then add 6 to get the next number: 8+6= 14 then add 6 to that to get the third number: 14+6= 20 so 8,14,20,26, and so on.
Let's try your choice: f(1) = 8 and f(n) = f(n - 1) + 6n; n > 1 when n=1, we get f(1)=8 (which is good) when n=2 we do f(2)= f(2-1) + 6*2 (replace n with 2 everywhere you see n) simplify to get: f(2) = f(1) + 12 f(1) is 8 (from the first step. so: f(2)= 8+12= 20 according to the rule, f(2)= 20 but the sequence goes 8,14,20,26... f(2) is 14. This rule is not the one we want.
oh ok so it would be second one
you can even check the 2nd choice: f(1) = 8 and f(n) = f(n - 1) + 6; n > 1 f(2)= f(2-1) + 6 f(2) = f(1) + 6 f(2) = 8+6 = 14 which works. This stuff is not too hard if you practice it.
yea im not to great with math i try to study a lot but im not to good
but is it ok if u could help me with one more question if possible?
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