Question

Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.

y = –2x^2 + x – 3

Answer 1

a 1 point in common; vertex on x-axis
b 2 points in common; vertex below x-axis
c 2 points in common; vertex above x-axis
d no points in common; vertex below x-axis

Answer 2

first find the discriminant which is (b^2-4ac) here b=1,a=-2,c=-3

Answer 3

its too late im done with this question

Answer 4

if b^2 – 4ac > 0 then two real solutions which are different.................(1)
if b^2 – 4ac = 0 then two real solutions which are equal.........................(2)
if b^2 – 4ac < 0 then two complex solutions which are different..............(3)
in ur problem
(b^2-4ac)=1-24=-23
so no (3) is valid so ur ans is
d no points in common; vertex below x-axis