What is the vertex and the equation of the axis of symmetry of the graph of y=x^2-6x-7?

Question

zzr0ck3r · Answer

for parabola $f(x) = ax^2+bx+c$ the vertex is $$(\frac{-b}{2a},f(\frac{-b}{2a}))$$ and the axis of symmetry is $x=\frac{-b}{2a}$

anonymous · Answer

Okay, I'm a bit confused. :o lol. Sorry, I'm terrible at math.

anonymous · Answer

Is it C?

zzr0ck3r · Answer

you have 
$x^2-6x-7$
compare that  to 
$ax^2+bx+c$

what is a?

anonymous · Answer

Oh, sorry, forgot I didn't give you the options.

a) vertex: (–16, 3)
a.o.s: x = –16

b) vertex: (–3, 20)
a.o.s: x = –3

c) vertex: (3,–16)
a.o.s: x = 3

d) vertex: (20, –3)
a.o.s: x = 20

pinksapphire · Answer

The correct answer is letter C.

anonymous · Answer

Thank you.

pinksapphire · Answer

Use a graphing Calculator to help you...

zzr0ck3r · Answer

just take the class for her....

anonymous · Answer

Lol. I already figured it was C, I just needed some confirmation. I understand the work though.