Question

how do you find the inverse of f(x) = ax + b ?

Answer 1

I do believe f(x) is the same as y
y=ax+b where a is the coefficient.
The inverse is where x is solved for when y is put in for it.
x=ay+b
x-b=ay
divide by a
(x-b)/a=y
I do believe I did that correctly.

Answer 2

You forgot to exchange "y" back to f(x)

Answer 3

I have been puzzled, as I understood
[f(x)] [inverse of f(x)] = 1

but sometimes we speak of arc sinx as the invers of sin x

Answer 4

Oops. ;-;

Answer 5

but that solution should not be called f(x) but perhaps
f^-1(x)

Answer 6

Yeah. ^

Answer 7

@barbie15
see the above discussion of inverse

Answer 8

Yeah You need the answer

Answer 9

This is just a simple linear function. Well that's what I understand as "ax", b is the constant.

Answer 10

f(f^-1(x)) = x

Answer 11

f(f^-1(x)) = a((x-b)/a) + b
= x - b + b
= x

Answer 12

Are you implying something different?

Like f(x) = 7x + 10, the inverse would be, f^-1(x) = (x - 10)/7

they cancel out, obviously, f(f^-1(x)) = 7((x-10)/7) + 10 = x - 10 + 10 = x