sin(3 theta)=-1
Sine attains -1 at an angle of \(\dfrac{3\pi}{2}\), so \[3\theta=\frac{3\pi}{2}\]
wait, what if it's 1, the negative one was an acident
In that case, the angle would be \(\dfrac{\pi}{2}\).
is there a way i could figure this out like if it were given to me on a test?
I'd suggesting memorizing the common angles associated with the unit circle and their corresponding triangles. http://i.stack.imgur.com/r8uHr.gif
thanks, and turns out the answer was pie over 6, 5 pie over 6 and 3 pie over 2
For example, if you were given the equation \[\cos2x=\frac{1}{2}\] then you'll know the angle must be \(\dfrac{\pi}{3}\) or \(\dfrac{5\pi}{3}\). Then, \[2x=\frac{\pi}{3}~~\Rightarrow~~x=\frac{\pi}{6}\\ 2x=\frac{5\pi}{3}~~\Rightarrow~~x=\frac{5\pi}{6}\]
I finally get it! thank you so much, that unit circle seriously helped. Is there a way i could reward you on this site (newbie over here)
Thanks is good enough! yw
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