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Mathematics 9 Online
OpenStudy (anonymous):

Use the Arc Length Formula for Polar Curves to calculate the arc length of the entire circle

OpenStudy (anonymous):

OpenStudy (anonymous):

where to begin? :|

OpenStudy (anonymous):

i would just put in the answer since it doesn't know how you did it

OpenStudy (anonymous):

@satellite73 i dont understand :|

OpenStudy (anonymous):

it it clear that this is a circle with diameter \(11a\) ?

OpenStudy (anonymous):

hm yes?

OpenStudy (anonymous):

k it is clear that the circumerence of a circle is \(\pi r^2\) ?

OpenStudy (anonymous):

yes?

OpenStudy (anonymous):

k then you are done with no work at all

OpenStudy (anonymous):

arc length = circumference

OpenStudy (anonymous):

so your saying the answer would be pi(11acostheta)^2 ??

OpenStudy (anonymous):

radius is \(\frac{11a}{2}\) are a is \[\left(\frac{11a}{2}\right)^2\pi\]

OpenStudy (anonymous):

wait wait i must be kidding circumference, not area!!

OpenStudy (anonymous):

\[C=2\pi r\]

OpenStudy (anonymous):

in your case \[C=2\times 11a \pi\] or \[22a\pi\]

OpenStudy (anonymous):

nope that is wrong too i should just shut up now the radius is \(\frac{11a}{2}\) the area is \[11a\pi\]

OpenStudy (anonymous):

damn two mistakes in one easy problem sorry

OpenStudy (anonymous):

haha oh gosh ! ok let me try to see if that is the answer. it did suggest that i use this formula...

OpenStudy (anonymous):

let me show you

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

you did it again! you were right !

OpenStudy (anonymous):

you can do it that way too, but it seems like a lot of work for a simple formula you should know (and i should know too lol)

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