Check my work?!
So heres the question \[\lim_{n \rightarrow \infty} \sum_{i=1}^{n} x i^9 - \frac{ 3\tan(x i }{ x i } Deltax\]
Heres how i solved
\[\int\limits_{0}^{\pi/3} \frac{ x^9-3\tan(x)dx }{ x }\]
My question is, is the "i" always ignored, or am i ignoring the i in this case because it is equal to 1
(Question asked express the limit as a definite intergral)
I will focus only on your personal question here. We are not "ignoring" the counter, " i ". Note that we count from 1 to n; this produces n terms that have to be combined (summed up). In the very end we take the limit of that result as n approaches infinity. As you're probably aware, this is a Riemann Sums problem.
We don't actually sum up hundreds and millions of individual terms (representing thin vertical slices of area), but rather separate the integrand so that you have, instead, sums that look like \[\sum_{i=1}^{n}1=n;~\sum_{i=1}^{n}i=\frac{ n(n+1) }{ 2 };~\sum_{i=1}^{n}i^2=\frac{ n(n+1)(2n+1) }{6 }\] and so on.
Please forgive me, but i need to get off the 'Net now. Good luck! By all means come back if you have further Riemann Sums problems to discuss.
Was my solved answer incorrect? but thank you!:)
One last thing: I'm not as familiar with the use of this method where trig functions are involved. I'd suggest that you choose another problem involving a polynomial that is at just the right level that you can solve it; work your way up to harder problems, and then, finally, tackle this one involving a trig function.
Is it possible that by \[\lim_{n \rightarrow \infty} \sum_{i=1}^{n} x i^9\Delta x\]
you actually meant this? \[\lim_{n \rightarrow \infty} \sum_{i=1}^{n} x _{i} ^{9} \Delta x\]??? |dw:1399732079904:dw|
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