Question

PLEASE HELP!!!!!!

(problem below)

Answer 1

numerator = 7^(1/3+12)
dnominator = 7^5/6

Answer 2

first solve (1/3+1/2) =(2+3)/6 =5/6

so numerator = 7^(1/3+12) =7^5/6
dnominator = 7^5/6

Answer 3

so is the final answer 7?

Answer 4

since numerator and denominator are same so how can their quotient be 7

Answer 5

so the final answer is 1?

Answer 6

yup

Answer 7

thanks :)

Answer 8

yw

Answer 9

\[\huge \frac{ \sqrt[3]{7}\sqrt{7}}{\sqrt[6]{7^5}}\]
\[\huge =\frac{7^{\frac{1}{3}} \times 7^{\frac{1}{2}}}{7^{\frac{5}{6}}}\]
\[\huge =\frac{7^{\frac{1}{3}+\frac{1}{2}}}{7^{\frac{5}{6}}}\]
\[\huge =\frac{7^{\frac{2+3}{2 \times3}}}{7^{\frac{5}{6}}}\]
\[\huge =\frac{7^{\frac{5}{6}}}{7^{\frac{5}{6}}}=7^{\frac{5}{6}-\frac{5}{6}}=7^0 =1\]
Hence 1 is the correct answer of the given problem.

@RosieF