Question

Calculate the mass of solid BaSO4 produced if 20.0ml of a 0.2 mol/L Ba(OH)2 solution is mixed with 40.0 ml of a 0.2 mol/L H2SO4 solution.

Answer 1

First, let's find the balanced equation. Since in this case, the stoichiometric ratio between all of them is one, this is not a problem

Answer 2

then determine which one is the limiting reactant (reagent). Ba(OH)2 is the limiting reactant, because you have less of it around. Then find the total number of mols of Ba(OH)2 that you have, change it to BaSO4 using stoichiometric ratio (1:1) to find the number of mols of products you have, then multiply by molar mass to get the mass produced