Question

The figure below shows a square ABCD and an equilateral triangle DPC.

Answer 1

so... What's the question?

Answer 2

Let me show you

Answer 3

Ted makes the chart shown below to prove that triangle APD is congruent to triangle BPC.

Statements Justifications
In triangles APD and BPC; DP = PC Sides of equilateral triangle DPC are equal
In triangles APD and BPC; AD = BC Sides of square ABCD are equal
In triangles APD and BPC; angle ADP = angle BCP Angle ADC = angle BCD = 90° so angle ADP = angle BCP = 60°
Triangles APD and BPC are congruent SAS postulate


What is the error in Ted's proof?
He writes the measure of angles ADP and BCP as 60° instead of 45°.

He uses the SAS postulate instead of AAS postulate to prove the triangles congruent.

He writes the measure of angles ADP and BCP as 60° instead of 30°.

He uses the SAS postulate instead of SSS postulate to prove the triangles congruent.

Answer 4

http://assets.openstudy.com/updates/attachments/4ff07e52e4b03c0c4887e773-katemarie123-1341161140196-marth2.jpg

Answer 5

do you have a picture or something? or is the problem just like this?

Answer 6

The problem looks like half of them are in a statement the other half in a justification

Answer 7

STATEMENTS
In triangles APD and BPC; DP = PC

In triangles APD and BPC; AD = BC

In triangles APD and BPC; angle ADP = angle BCP

Triangles APD and BPC are congruent

Answer 8

JUSTIFICATION
Sides of equilateral triangle DPC are equal

Sides of square ABCD are equal

Angle ADC = angle BCD = 90° so angle ADP = angle BCP = 60°

SAS postulate

Answer 9

The link is a pic of the triangle

Answer 10

answer is the third one

Answer 11

Thank you

Answer 12

just think about it... if you have an equilateral triangle, then the sum of that angle and the remaining angle can't be larger than 90 right?

Answer 13

Thats true!

Answer 14

in the problem it said angle ADP is 60, which can't be true

Answer 15

Yeah you're right