In a 45°-45°-90° triangle, the length of the hypotenuse is 11. Find the length of one of the legs.

Question

johnweldon1993 · Answer

A 45 45 90 triangle has the other 2 legs of the same length...

and the hypotenuse...is the length of 1 of those legs...times √2

So we need to solve

$$\large \sqrt{2}x = 11$$

anonymous · Answer

1.41x=11?

johnweldon1993 · Answer

Well I wouldnt approximate just yet...I would simply do

$$\large x = \frac{11}{\sqrt{2}}$$

anonymous · Answer

thanks

anonymous · Answer

@johnweldon1993 do you know how i would do this problem? Which of the following are not the lengths of the sides of a 30°-60°-90° triangle?

johnweldon1993 · Answer

Sure...

So for that one...the side ratios are 1:2:√3

|dw:1399738271969:dw|

So whatever the shortest side is...make that X

Then the hypotenuse will be 2 times that...

And the length of the 3rd leg will be the smallest leg..times $\sqrt{3}$

anonymous · Answer

how do i start figureing out what x is

johnweldon1993 · Answer

....judging from the question...you should have choices...

anonymous · Answer

$$A.\frac{ 1 }{ 2}, \frac{ \sqrt{3} }{ 2 },1   $$

anonymous · Answer

$$B.\frac{ 5 }{ 2 },\frac{ \sqrt[5]{?3} }{ 2},10$$

anonymous · Answer

$$C.\sqrt{2},\sqrt{6},\sqrt[2]{2}$$

anonymous · Answer

$$D.3,\sqrt[3]{3},6$$